Bonjour,
Résoudre l'équation:
[tex] \frac{x + 4}{3} - \frac{x - 1}{12} = \frac{3}{4} \\ \\ \frac{ \red{4}(x + 4)}{ \red{4 \times } 3} - \frac{x - 1}{12} = \frac{3}{4} \\ \\ \frac{4x + 16}{12} - \frac{x - 1}{12} = \frac{3}{4} \\ \\ \frac{ - 3x + 17}{12} = \frac{3}{4} [/tex]
[tex] - 3x + 17 = \blue{12 \times } \frac{3}{4} \\ \\ 3x + 17 = \frac{36}{4} \\ \\ - 3x + 17 = 9 \: \: \: \\ - 3x \: \: \: \: \: \: \: \: = - 8 \: \\ 3x \: \: \: \: \: \: \: = 8 \\ \green{ \boxed{ \purple{x \: \: \: \: \: \: \: \: \: = \frac{8}{3} }}}[/tex]
Bonne journée
