Bonsoir,
[tex]2x^2-6x+2y^2+3y+4=0\\\\\Longleftrightarrow 2(x^2-3x+y^2+\frac{3}{2} y+2=0\\\\\Longleftrightarrow x^2-2*\frac{3}{2} x+\frac{9}{4} +y^2+2\frac{3}{4} y+\frac{9}{16} +2-\frac{9}{4}-\frac{9}{16} =0\\\\\Longleftrightarrow (x-\frac{3}{2})^2+(y+\frac{3}{4})^2=\frac{13}{16} \\[/tex]
2. Cercle de centre (3/2,-3/4) et de rayon √13 /4.
