[tex] \frac{5}{4} - \frac{9}{13} \times \frac{65}{81} + \frac{11}{36} = \frac{5}{4} - \frac{585}{1053} + \frac{11}{36} = \frac{5}{4} - \frac{5}{9} + \frac{11}{36} = \frac{45}{36} - \frac{20}{36} + \frac{11}{36 } = \frac{36}{36} = 1[/tex]
pour la A
[tex] \frac{2}{3} - \frac{7}{3} ×(\frac{3}{2} -2) = \frac{2}{3} - \frac{7}{3}×(\frac{3}{2} -\frac{4}{2}) =\frac{2}{3} - \frac{7}{3} × \frac{-1}{2} = \frac{2}{3} - \frac{-7}{6} = \frac{4}{6} - \frac{-7}{6} = \frac{11}{6}[/tex]
pour la B
[tex] \frac{40}{27} × \frac{-12}{15} - \frac{5}{3} = \frac{-480}{405} - \frac{5}{3} = \frac{32}{27}
[/tex]
