Bonjour,
A=(1sur4-1sur5)x(7+37sur9)
[tex]A=(\dfrac{1}{4}-\dfrac{1}{5})\times(7+\dfrac{37}{9})\\\\A=(\dfrac{5}{20}-\dfrac{4}{20})\times(\dfrac{63}{9}+\dfrac{37}{9})\\\\A=\dfrac{1}{20}\times\dfrac{100}{9}\\\\A=\dfrac{5}{9}[/tex]
B=(1sur3+5sur6+3sur2)
[tex]B=\dfrac{1}{3}+\dfrac{5}{6}+\dfrac{3}{2}\\\\B=\dfrac{2}{6}+\dfrac{5}{6}+\dfrac{9}{6}\\\\B=\dfrac{16}{6}=\dfrac{8}{3}[/tex]