c'est résoudre je suppose ?
1)(3x-4)^2=100
(3x-4)^2-100 = 0
(3x-4)^2-10² = 0
(3x - 4 - 10)(3x - 4 + 10) = 0
(3x - 14)(3x + 6) = 0
3(3x - 14)(x + 2) = 0
2 solutions : x = -14/3 ou x = -2
2) (2x+7)^2=1
(2x+7)^2 - 1² = 0
(2x+7-1)(2x+7+1) = 0
(2x+6)(2x+8) = 0
4(x+3)(x+4) = 0
2 solutions : x = -3 ou x = -4
3) (x-1)^2=(x-7)^2
(x-1)^2 - (x-7)^2 = 0
(x - 1 - x + 7)(x - 1 + x - 7) = 0
8(2x - 8) = 0
16(x - 4) = 0
1 seul solution : x = 4
4) (3x-2)^2=x^2
(3x-2)^2 - x^2 = 0
(3x - 2 -x) (3x - 2 +x) = 0
(2x - 2)(4x - 2) = 0
4(x-1)(2x - 1) = 0
2 solutions : x = 1 ou x = 1/2
En espérant t'avoir aidé.
