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Bonjour
Vous pouvez développer et réduire :
A = 2x(x + 3)
B = –7y²(–5 – 2y²)
C = (x + 5)(x + 1)
D = (2x – 5) (x + 4)
E = (4 – a)²
F = (2x + 3)²
G = (4 – 7x)(4 + 7x)
H = (x + 4)(x – 6) + (–1 + x)(x – 7)
I = –3(a² + 2) – (a – 3)(2a + 7)
J = 4 – (2x + 1)²

Merci ​

Sagot :

Bjr

Développer puis réduire :

A = 2x(x + 3)

A = 2x² + 6x

B = –7y²(–5 – 2y²)

B = 35y² + 14y

C = (x + 5)(x + 1)

C = x² + x + 5x + 5

C = x² + 6x + 5

D = (2x – 5) (x + 4)

D = 2x² + 8x – 5x – 20

D= 2x² + 3x – 20

E = (4 – a)²

E = 4² – 2 × 4 × a + a²

E = 16 – 8a + a²

F = (2x + 3)²

F = (2x)² + 2 × 2x × 3 + 3²

F = 4x² + 12x + 9

G = (4 – 7x)(4 + 7x)

G = 4² – (7x)²

G = 16 – 49x²

H = (x + 4)(x – 6) + (–1 + x)(x – 7)

H = (x² – 6x + 4x – 24) + (–x + 7 + x² – 7x)

H = (x² – 2x – 24) + (x² – 8x + 7)

H = x² – 2x – 24 + x² – 8x + 7

H = 2x² – 10x – 17

I = –3(a² + 2) – (a – 3)(2a + 7)

I = (–3a² – 6) – (2a² + 7a – 6a – 21)

I = (–3a² – 6) – (2a² + a – 21)

I = –3a² – 6 – 2a² – a + 21

I = –5a² – a + 15

J = 4 – (2x + 1)²

J = 4 – [(2x)² + 2 × 2x × 1 + 1²]

J = 4 – (4x² + 4x + 1)

J = 4 – 4x² – 4x – 1

J = 3 – 4x² – 4x

Bonne Année !

Réponse :

Bonjour et Bonne année !

Explications étape par étape :

Développement

A = 2x (x + 3)

A = 2x² + 6x

B = –7y²(–5 – 2y²)

B = + 35 y² + 14 y⁴

C = (x + 5)(x + 1)

C = x² + x + 5x + 5

C = x² +6x + 5

D = (2x – 5) (x + 4)

D = 2x² + 8x - 5x - 20

D = 2x² + 3x - 20

E = (4 – a)²

E = 16 -8a + a²

F = (2x + 3)²

F = 4x² + 12x + 9

G = (4 – 7x)(4 + 7x)

G = 16 + 28x - 28x - 49x²

G = - 49x² + 16

H = (x + 4)(x – 6) + (–1 + x)(x – 7)

H = x² - 6x + 4x -24 + (-x +7 + x² -7x)

H = x² -2x -24 -8x +7 + x²

H = +2x² -10x -17

I = –3(a² + 2) – (a – 3)(2a + 7)

I = -3a² -6 - ( 2a² + 7a -6a -21)

I = -3a² -6 - ( 2a² +a -21)

I = -3a² -6 -2a² -a + 21

I = -5a² +15 -a

J = 4 – (2x + 1)²

J = 4 - ( 4x² + 4x + 1)

J = 4 - 4x² -4x -1

J = - 4x² -4x +3